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For the function \(f(x)=\{2x\}\), where \(\{y\}\) denotes the fractional part of y, what is the value of \(f(x)\) at \(x=1.35\)?फलन \(f(x)=\{2x\}\) में, जहाँ \(\{y\}\) y का भिन्नात्मक भाग दर्शाता है, \(x=1.35\) पर \(f(x)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(0.7\)\(0.7\)
Substituting \(x=1.35\) gives \(2x=2(1.35)=2.7\). Removing the integer part 2 leaves the fractional part \(0.7\), so \(f(1.35)=0.7\). Option B, \(2.7\), is the value of \(2x\) before taking its fractional part. In an exam, use \(\{y\}=y-\lfloor y\rfloor\) to evaluate such functions quickly.\(x=1.35\) रखने पर \(2x=2(1.35)=2.7\) मिलता है। 2.7 का भिन्नात्मक भाग पूर्णांक भाग 2 हटाने पर \(0.7\) है, इसलिए \(f(1.35)=0.7\)। विकल्प B \(2.7\) पूरा मान है, भिन्नात्मक भाग नहीं। परीक्षा में \(\{y\}=y-\lfloor y\rfloor\) का उपयोग करके शीघ्रता से मान निकालें।
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