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For the function \(f(x)=\operatorname{sgn}(2-x)\), what is the value of \(f(x)\) when \(x>2\)?फलन \(f(x)=\operatorname{sgn}(2-x)\) में, यदि \(x>2\), तो \(f(x)\) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: -1-1
When \(x>2\), we have \(2-x<0\). The signum function has value \(-1\) for a negative argument; therefore, \(f(x)=\operatorname{sgn}(2-x)=-1\). Exam tip: \(\operatorname{sgn}(y)\) equals \(-1\) for \(y<0\), \(0\) for \(y=0\), and \(1\) for \(y>0\).जब \(x>2\), तब \(2-x<0\) होता है। साइनम फलन में किसी ऋणात्मक संख्या का मान \(-1\) होता है, इसलिए \(f(x)=\operatorname{sgn}(2-x)=-1\)। ध्यान रखें: \(\operatorname{sgn}(y)\) का मान \(y<0\) पर \(-1\), \(y=0\) पर \(0\), और \(y>0\) पर \(1\) होता है।
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