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What is the axis of symmetry of the graph of \(f(x)=2x^2-8x+1\)?फलन \(f(x)=2x^2-8x+1\) के आलेख का सममिति-अक्ष क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(x=2\)\(x=2\)
For a quadratic function \(f(x)=ax^2+bx+c\), the axis of symmetry is \(x=-\frac{b}{2a}\). Here, \(a=2\) and \(b=-8\), so \(x=-\frac{-8}{2\cdot2}=2\). Therefore, the correct answer is \(x=2\). Remember that the axis of symmetry is a vertical line, so \(y=2\) cannot be correct here.द्विघात फलन \(f(x)=ax^2+bx+c\) के आलेख का सममिति-अक्ष \(x=-\frac{b}{2a}\) होता है। यहाँ \(a=2\) और \(b=-8\), इसलिए \(x=-\frac{-8}{2\cdot2}=2\)। अतः सही उत्तर \(x=2\) है। ध्यान रखें कि सममिति-अक्ष ऊर्ध्वाधर रेखा है; इसलिए \(y=2\) इस प्रश्न का सही उत्तर नहीं हो सकता।
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