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For the function \(f(x)=\operatorname{sgn}(4-x)\), what is the value of \(f(x)\) when \(x<4\)?फलन \(f(x)=\operatorname{sgn}(4-x)\) में, यदि \(x<4\) हो, तो \(f(x)\) का मान क्या होगा?
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Correct answer:सही उत्तर: 11
When \(x<4\), we have \(4-x>0\). The signum function has value \(1\) for a positive argument, so \(f(x)=\operatorname{sgn}(4-x)=1\). The value 0 occurs only at \(x=4\), while -1 occurs when \(x>4\). Exam tip: remember that \(\operatorname{sgn}(y)=1\) for \(y>0\), 0 for \(y=0\), and -1 for \(y<0\).जब \(x<4\), तब \(4-x>0\) होता है। साइनम फलन में धनात्मक संख्या का मान \(1\) होता है, इसलिए \(f(x)=\operatorname{sgn}(4-x)=1\)। विकल्प 0 केवल \(x=4\) पर और विकल्प -1 \(x>4\) पर प्राप्त होता है। परीक्षा में याद रखें: \(\operatorname{sgn}(y)=1\) यदि \(y>0\), 0 यदि \(y=0\), और -1 यदि \(y<0\)।
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