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What is the range of (f(x)=\frac{1}{(x+1)^2}+3)?फलन (f(x)=\frac{1}{(x+1)^2}+3) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((3,\infty))((3,\infty))
(\frac{1}{(x+1)^2}>0), so the function is greater than (3) but never equal to (3). Hence the range is ((3,\infty)).(\frac{1}{(x+1)^2}>0), इसलिए फलन (3) से बड़ा है लेकिन (3) के बराबर नहीं। अतः परिसर ((3,\infty)) है।
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