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What is the range of (f(x)=\sqrt{5-x}+2)?फलन (f(x)=\sqrt{5-x}+2) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([2,\infty))([2,\infty))
Since (\sqrt{5-x}\ge 0), (f(x)\ge 2). The square root can grow as (x) decreases, so the range is ([2,\infty)).(\sqrt{5-x}\ge 0), इसलिए (f(x)\ge 2)। (x) घटाने पर वर्गमूल बड़ा हो सकता है, इसलिए परिसर ([2,\infty)) है।
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