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What is the starting point of (f(x)=\sqrt{x+2}-3)?फलन (f(x)=\sqrt{x+2}-3) का प्रारंभिक बिंदु कौन सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((-2,-3))((-2,-3))
(\sqrt{x+2}) starts when (x+2=0), that is (x=-2). The outside (-3) makes the starting point ((-2,-3)).(\sqrt{x+2}) तब शुरू होता है जब (x+2=0), अर्थात (x=-2)। बाहर (-3) होने से प्रारंभिक बिंदु ((-2,-3)) है।
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