0 reads0 ratings0 helpful
What is the horizontal asymptote of the function \(f(x)=\frac{1}{x-1}-2\)?फलन \(f(x)=\frac{1}{x-1}-2\) का क्षैतिज आसिम्प्टोट कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(y=-2\)\(y=-2\)
As \(|x|\) becomes very large, \(\frac{1}{x-1}\to 0\), so \(f(x)\to -2\). Therefore, the horizontal asymptote is \(y=-2\). The line \(x=1\) is the vertical asymptote, not the horizontal one. Exam tip: For a function of the form \(\frac{a}{x-h}+k\), the horizontal asymptote is \(y=k\).जब \(|x|\) बहुत बड़ा होता है, तब \(\frac{1}{x-1}\to 0\), इसलिए \(f(x)\to -2\)। अतः क्षैतिज आसिम्प्टोट \(y=-2\) है। \(x=1\) ऊर्ध्वाधर आसिम्प्टोट है, क्षैतिज नहीं। परीक्षा-युक्ति: \(\frac{a}{x-h}+k\) के लिए क्षैतिज आसिम्प्टोट \(y=k\) होता है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
