Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

Which point is not on the graph of (f(x)=\sqrt{x})?

Answer and explanation

Correct answer: ((-1,1))

The direct answer is D: \\((-1,1)\\) is not on the graph. For \\(y=\sqrt{x}\\), the input x must be non-negative, and the point must satisfy y equal to the principal square root of x. Check A: \\(\sqrt9=3\\), so \\( (9,3)\\) is on the graph. Check B: \\(\sqrt{16}=4\\), so \\( (16,4)\\) is on it. Check C: \\(\sqrt1=1\\), so \\( (1,1)\\) is on it. Check D: x=-1 is outside the real domain of the square-root function; \\(\sqrt{-1}\\) is not a real number, so \\((-1,1)\\) cannot lie on this real graph. D is correct. A, B and C each satisfy the equation exactly. Do not confuse \\(y=\sqrt{x}\\) with \\(y^2=x\\), which would also include negative y-values; the square-root function uses the non-negative principal value.

Related tags

Standard-FunctionsSquare-Root-FunctionPoint-Check

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Add Muft Shiksha to your Home Screen

In Safari, tap Share, then Add to Home Screen.