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What is the minimum value of f(x)=x^2?

Answer and explanation

Correct answer: 0

The governing concept is the range and minimum of the square function. For every real number x, the square x^2 is non-negative, so x^2 ≥ 0. Equality is achieved when x=0, because 0^2=0. Therefore the least, or minimum, value of f(x)=x^2 is 0, making option A correct. The value 1 is attained at x=1 and x=-1, but it is not the least value because values between 0 and 1 are also possible. The value -1 cannot occur because a real square is never negative. The function does have a minimum, located at the vertex (0,0) of its upward-opening parabola.

Related tags

Relations-FunctionsQuadratic-FunctionMinimum-ValueGraphs Of Standard FunctionsRelations And FunctionsMathematicsClass 11 Mcq

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