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If f(x)=x²+1 and g(x)=2x, what is the range of (f+g)(x)?

Answer and explanation

Correct answer: [0,∞)

The sum of functions is obtained by adding their outputs: (f+g)(x)=f(x)+g(x)=x²+1+2x. Completing the square gives x²+2x+1=(x+1)². Every real square is non-negative, so the expression can never be less than zero. Its minimum value is 0, attained when x+1=0, or x=−1. As x moves away from −1, (x+1)² can take every non-negative value, so no positive values are missed. Hence the range is [0,∞), making option A correct. Option B incorrectly assumes the minimum is 1, while options C and D ignore the square form or reverse its restriction.

Related tags

Relations-FunctionsAlgebra-Real-FunctionsRangeSum-Of-FunctionsAlgebra Of Real FunctionsRelations And FunctionsMathematicsClass 11 Mcq

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