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If (f(x)=\frac{1}{x-2}) and (g(x)=\frac{1}{x+4}), what is ((f-g)(x))?यदि (f(x)=\frac{1}{x-2}) और (g(x)=\frac{1}{x+4}) हैं, तो ((f-g)(x)) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{6}{(x-2)(x+4)})(\frac{6}{(x-2)(x+4)})
((f-g)(x)=\frac{x+4-(x-2)}{(x-2)(x+4)}=\frac{6}{(x-2)(x+4)}). Keep numerator signs carefully while using a common denominator.((f-g)(x)=\frac{x+4-(x-2)}{(x-2)(x+4)}=\frac{6}{(x-2)(x+4)})। समान हर बनाते समय अंश के चिन्ह ध्यान से रखें।
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