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If (f(x)=\frac{x^2+1}{x}) and (g(x)=\frac{x^2-1}{x}), what is ((f-g)(x))?यदि (f(x)=\frac{x^2+1}{x}) और (g(x)=\frac{x^2-1}{x}) हैं, तो ((f-g)(x)) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{2}{x}), (x\ne 0)(\frac{2}{x}), (x\ne 0)
With a common denominator, (f-g=\frac{x^2+1-(x^2-1)}{x}=\frac{2}{x}), where (x\ne 0). In subtraction, both signs of the second numerator change.समान हर से (f-g=\frac{x^2+1-(x^2-1)}{x}=\frac{2}{x}), जहां (x\ne 0)। घटाव में दूसरे अंश के दोनों चिन्ह बदलते हैं।
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