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If \(f(x)=x^2-3x+2\) and \(g(x)=x-1\), what is the value of \(\left(\frac{f}{g}\right)(2)\)?

Answer and explanation

Correct answer: 0

For the quotient function, \(\left(\frac{f}{g}\right)(x)=\frac{f(x)}{g(x)}\). Here, \(f(2)=2^2-3(2)+2=0\) and \(g(2)=2-1=1\), so \(\left(\frac{f}{g}\right)(2)=\frac{0}{1}=0\). Option D is incorrect because the denominator, \(g(2)=1\), is not zero. Exam tip: evaluate the numerator and denominator separately and check that the denominator is non-zero.

Related tags

Relations And FunctionsAlgebra Of Real FunctionsQuotient Of FunctionsFunction EvaluationMathematicsClass 11 Mcq

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