0 reads0 ratings0 helpful
If (f(x)=\frac{x}{x^2-4}) and (g(x)=\frac{1}{x-2}), what is the domain of ((f+g)(x))?यदि (f(x)=\frac{x}{x^2-4}) और (g(x)=\frac{1}{x-2}) हैं, तो ((f+g)(x)) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\mathbb{R}\setminus{-2,2})(\mathbb{R}\setminus{-2,2})
(x^2-4=(x-2)(x+2)), so (x=2) and (x=-2) are forbidden. For a sum, take the intersection of the domains.(x^2-4=(x-2)(x+2)), इसलिए (x=2) और (x=-2) निषिद्ध हैं। योग में दोनों फलनों के प्रांत का प्रतिच्छेद लें।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
