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If (f(x)=\frac{1}{\sqrt{x-2}}) and (g(x)=x^2), what is the domain of ((f+g)(x))?यदि (f(x)=\frac{1}{\sqrt{x-2}}) और (g(x)=x^2) हैं, तो ((f+g)(x)) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((2,\infty))((2,\infty))
The denominator has (\sqrt{x-2}), so (x-2>0), meaning (x>2). A square root in the denominator cannot be zero.हर में (\sqrt{x-2}) है, इसलिए (x-2>0), यानी (x>2)। हर वाले वर्गमूल में शून्य भी निषिद्ध होता है।
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