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If \(f(x)=|x|\) and \(g(x)=x\), for which values of \(x\) will \((f-g)(x)=0\)?

Answer and explanation

Correct answer: \(x\ge 0\)

Here, \((f-g)(x)=f(x)-g(x)=|x|-x\). For \(x\ge 0\), \(|x|=x\), so \(|x|-x=0\). For \(x<0\), \(|x|=-x\), giving \(|x|-x=-2x\), which is not zero. Hence option A is correct; option C is incomplete because every non-negative value, not just zero, is a solution. Exam tip: For modulus expressions, always check the cases \(x\ge 0\) and \(x<0\).

Related tags

Relations-FunctionsAlgebra-Real-FunctionsModulusDifference-Of-FunctionsPiecewise-AnalysisAlgebra Of Real FunctionsRelations And FunctionsMathematics

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