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If (f(x)=\frac{1}{x-2}) and (g(x)=\frac{1}{x+2}) then what is ((f-g)(x))?यदि (f(x)=\frac{1}{x-2}) और (g(x)=\frac{1}{x+2}) हैं तो ((f-g)(x)) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{4}{x^2-4}), (x\ne \pm 2)\(\frac{4}{x^2-4}), (x\ne \pm 2)
((f-g)(x)=\frac{1}{x-2}-\frac{1}{x+2}=\frac{4}{x^2-4}), where (x\ne \pm 2). Keep restrictions while multiplying denominators.((f-g)(x)=\frac{1}{x-2}-\frac{1}{x+2}=\frac{4}{x^2-4}), जहाँ (x\ne \pm 2)। हरों का गुणन करते समय प्रतिबंध रखें।
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