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If f(x)=x^2-1 and g(x)=2x, what is the minimum value of (f+g)(x)?

Answer and explanation

Correct answer: -2

The governing concept is finding the minimum value of a quadratic by completing the square. Add the two functions pointwise: (f+g)(x)=(x²-1)+2x=x²+2x-1. Now rewrite this expression as x²+2x-1=(x+1)²-2. For every real x, a square is non-negative, so (x+1)²≥0. Consequently, the least possible value of the whole expression is 0-2=-2. This value is attained when x+1=0, or x=-1, so the minimum actually exists. Option A is correct. Option B ignores the contribution of the linear term, while options C and D are larger than the vertex value and therefore cannot be the minimum.

Related tags

Relations-FunctionsQuadratic-MinimumFunction-SumAlgebra-Of-Real-FunctionsAlgebra Of Real FunctionsRelations And FunctionsMathematicsClass 11 Mcq

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