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If \(f(x)=x^2+x\) and \(g(x)=x^2-x\), what is the range of \((f+g)(x)\)?

Answer and explanation

Correct answer: \([0,\infty)\)

\((f+g)(x)=f(x)+g(x)=(x^2+x)+(x^2-x)=2x^2\). Since \(2x^2\geq 0\) for every real \(x\), and the minimum value \(0\) is attained at \(x=0\), the range is \([0,\infty)\). Option D is incorrect because the minimum is 0, not 1. Exam tip: a positive multiple of \(x^2\) has a range beginning at its minimum value, 0.

Related tags

Relations-And-FunctionsAlgebra-Of-Real-FunctionsRange-Of-Sum-FunctionsQuadratic-FunctionsAlgebra Of Real FunctionsRelations And FunctionsMathematicsClass 11 Mcq

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