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If \(f(x)=x^2-4x+4\) and \(g(x)=x-2\) then what is the value of \(\left(\frac{f}{g}\right)(3)\)?यदि \(f(x)=x^2-4x+4\) और \(g(x)=x-2\) हैं तो \(\left(\frac{f}{g}\right)(3)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (1)(1)
\(\frac{f}{g}=\frac{(x-2)^2}{x-2}=x-2\) where (x\ne 2), so at \(x=3\) the value is (1). First note the restriction then substitute.\(\frac{f}{g}=\frac{(x-2)^2}{x-2}=x-2\) जहाँ (x\ne 2), इसलिए \(x=3\) पर मान (1) है। पहले प्रतिबंध फिर मान रखें।
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