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If (f(x)=x^2+1) and (g(x)=\frac{1}{x^2+1}) then what is the domain of ((fg)(x))?यदि (f(x)=x^2+1) और (g(x)=\frac{1}{x^2+1}) हैं तो ((fg)(x)) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\mathbb{R})\(\mathbb{R})
Since (x^2+1>0) for all real (x), the denominator is never zero. Therefore the domain is (\mathbb{R}).क्योंकि (x^2+1>0) सभी वास्तविक (x) के लिए है, हर कभी शून्य नहीं होता। इसलिए प्रांत (\mathbb{R}) है।
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