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If \(f(x)=x^2-4\) and \(g(x)=x-2\) then what is the simplified form and restriction of \(\left(\frac{f}{g}\right)(x)\)?यदि \(f(x)=x^2-4\) और \(g(x)=x-2\) हैं तो \(\left(\frac{f}{g}\right)(x)\) का सरल रूप और प्रतिबंध क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x+2), (x\ne 2)(x+2), (x\ne 2)
\(\left(\frac{f}{g}\right)(x)=\frac{x^2-4}{x-2}=x+2\) but (x\ne 2). Even after simplifying do not forget the original denominator restriction.\(\left(\frac{f}{g}\right)(x)=\frac{x^2-4}{x-2}=x+2\) पर (x\ne 2)। सरल करने के बाद भी मूल हर का प्रतिबंध न भूलें।
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