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If \(f(x)=x^2+1\) and \(g(x)=x^2-1\), when is \(\left(\frac{f}{g}\right)(x)\) greater than (1)?यदि \(f(x)=x^2+1\) और \(g(x)=x^2-1\) हों, तो \(\left(\frac{f}{g}\right)(x)\) (1) से अधिक कब है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(x<-1\) or \(x>1\)\(x<-1\) या \(x>1\)
\(\frac{x^2+1}{x^2-1}>1\) gives \(\frac{2}{x^2-1}>0\), so \(x^2-1>0\). Checking the denominator sign is essential.\(\frac{x^2+1}{x^2-1}>1\) से \(\frac{2}{x^2-1}>0\), अतः \(x^2-1>0\)। हर का संकेत जांचना जरूरी है।
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