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If (f(x)=\frac{x^2-4}{x+2}) and (g(x)=x-2), where is ((f-g)(x)) equal to (0)?यदि (f(x)=\frac{x^2-4}{x+2}) और (g(x)=x-2) हों, तो ((f-g)(x)) किस पर (0) है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: For every (x\ne -2)हर (x\ne -2) पर
(f(x)=x-2), but (x=-2) is excluded, so the difference is (0) for all (x\ne -2). Domain restriction is part of the answer.(f(x)=x-2) पर (x=-2) हटता है, इसलिए अंतर (0) सभी (x\ne -2) पर है। प्रांत प्रतिबंध उत्तर का हिस्सा है।
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