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If (f(x)=x^2+4x) and (g(x)=4), for which (x) is ((f+g)(x)) zero?

Answer and explanation

Correct answer: (x=-2)

The direct answer is option A, \(x=-2\). Function addition is performed pointwise: \((f+g)(x)=f(x)+g(x)\). Substituting the given functions gives \(x^2+4x+4\). This is the perfect square \((x+2)^2\), because \((x+2)^2=x^2+4x+4\). A square is zero only when its base is zero, so \(x+2=0\), giving \(x=-2\). Option A is therefore correct. Option B, \(x=2\), gives \((4+8+4)=16\), not zero. Option C, \(x=0\), gives 4, not zero. Option D, \(x=-4\), gives \(16-16+4=4\), not zero. The word zero means the output of the combined function, not necessarily the input. Memory cue: look for \(x^2+2ax+a^2=(x+a)^2\), then set the bracket equal to zero.

Related tags

Relations-FunctionsZerosQuadratic

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