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If (f(x)=x^2-6x+10) and (g(x)=x-1), what is the minimum value of ((f-g)(x))?यदि (f(x)=x^2-6x+10) और (g(x)=x-1) हों, तो ((f-g)(x)) का न्यूनतम मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (-\frac{9}{4})(-\frac{9}{4})
((f-g)(x)=x^2-7x+11=(x-\frac{7}{2})^2-\frac{5}{4}), so the minimum is (-\frac{5}{4}). Check options carefully.((f-g)(x)=x^2-7x+11=(x-\frac{7}{2})^2-\frac{5}{4}) नहीं, सही स्थिर मान से न्यूनतम (-\frac{5}{4}) है। विकल्पों में त्रुटि जांचें।
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