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If (f(x)=\sqrt{9-x^2}) and (g(x)=\frac{1}{x}), what is the domain of ((f+g)(x))?यदि (f(x)=\sqrt{9-x^2}) और (g(x)=\frac{1}{x}) हों, तो ((f+g)(x)) का प्रांत क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [-3,3]\setminus{0} )( [-3,3]\setminus{0} )
The root needs (9-x^2\ge 0), so (x\in[-3,3]), and (x\ne 0). The domain of the sum is the intersection.मूल के लिए (9-x^2\ge 0), इसलिए (x\in[-3,3]), और (x\ne 0)। योग का प्रांत दोनों शर्तों का प्रतिच्छेद है।
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