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If \(f(x)=x^2+2x+2\) and \(g(x)=x+1\), what is the minimum value of ((f-g)(x))?यदि \(f(x)=x^2+2x+2\) और \(g(x)=x+1\) हैं, तो ((f-g)(x)) का न्यूनतम मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{3}{4}\)\(\frac{3}{4}\)
\((f-g)(x)=x^2+x+1=\left(x+\frac{1}{2}\right)^2+\frac{3}{4}\). Therefore the minimum is \(\frac{3}{4}\).\((f-g)(x)=x^2+x+1=\left(x+\frac{1}{2}\right)^2+\frac{3}{4}\)। इसलिए न्यूनतम \(\frac{3}{4}\) है।
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