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If (f(x)=\frac{1}{x}) and (g(x)=x^2), how many real solutions does ((f+g)(x)=2) have?यदि (f(x)=\frac{1}{x}) और (g(x)=x^2) हैं, तो ((f+g)(x)=2) के वास्तविक हल कितने हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (2)(2)
The equation (x^2+\frac{1}{x}=2) gives (x^3-2x+1=0=(x-1)(x^2+x-1)). Since (x\neq0), count all valid real roots carefully.समीकरण (x^2+\frac{1}{x}=2) से (x^3-2x+1=0=(x-1)(x^2+x-1)) मिलता है। (x\neq0) होने पर तीन में से दो वास्तविक हल अलग-अलग हैं?
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