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If (f(x)=\frac{x}{x-1}) and (g(x)=\frac{x}{x+1}), what is ((f-g)(x))?यदि (f(x)=\frac{x}{x-1}) और (g(x)=\frac{x}{x+1}) हैं, तो ((f-g)(x)) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \frac{2x}{x^2-1} )( \frac{2x}{x^2-1} )
(\frac{x}{x-1}-\frac{x}{x+1}=\frac{x[(x+1)-(x-1)]}{x^2-1}=\frac{2x}{x^2-1}). Keep brackets correct while taking a common denominator.(\frac{x}{x-1}-\frac{x}{x+1}=\frac{x[(x+1)-(x-1)]}{x^2-1}=\frac{2x}{x^2-1})। समान हर बनाते समय कोष्ठक सही रखें।
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