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If (f(x)=x^2) and (g(x)=|x|), what is the minimum value of (f-g)?यदि (f(x)=x^2) और (g(x)=|x|) हैं, तो (f-g) का न्यूनतम मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (-\frac{1}{4})(-\frac{1}{4})
The expression is (x^2-|x|). Put (t=|x|\ge0), then (t^2-t) has minimum (-\frac{1}{4}). For hard modulus questions, using (t) is helpful.मान (x^2-|x|) है, (t=|x|\ge0) रखने पर (t^2-t) का न्यूनतम (-\frac{1}{4}) है। कठिन प्रश्नों में मापांक को (t) से बदलना उपयोगी है।
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