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If f(x) = x²−4x+4 and g(x) = x−2, where is (f/g) zero?

Answer and explanation

Correct answer: Nowhere

First form the quotient while respecting its domain. Since x²−4x+4 = (x−2)², we have (f/g)(x) = (x−2)²/(x−2) = x−2, but this cancellation is valid only for x ≠ 2 because the original denominator g(x) is zero at x = 2. A zero of a function must be an allowed domain value at which the function itself equals zero. The simplified expression x−2 would be zero at x = 2, but x = 2 is excluded from the original quotient, so the graph has a removable hole there rather than a zero. Consequently the quotient has no zero in its domain, and option A is correct. Option B ignores the domain restriction; C does not make x−2 zero; and D is false because the quotient is not zero for every allowed x.

Related tags

Relations-FunctionsQuotient-FunctionsDomainZeros-Of-FunctionsAlgebra Of Real FunctionsRelations And FunctionsMathematicsClass 11 Mcq

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