If (f(x)=\sqrt{9-x^2}) and (g(x)=\frac{1}{x}), what is the domain of (fg)?यदि (f(x)=\sqrt{9-x^2}) और (g(x)=\frac{1}{x}) हैं, तो (fg) का डोमेन क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [-3,3]-{0} )( [-3,3]-{0} )
For (\sqrt{9-x^2}), (-3\le x\le3), and for (\frac{1}{x}), (x\neq0). Hence the domain is ( [-3,3]-{0} ).(\sqrt{9-x^2}) के लिए (-3\le x\le3) और (\frac{1}{x}) के लिए (x\neq0) है। अतः डोमेन ( [-3,3]-{0} ) है।
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