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If (f(x)=\frac{x-1}{x+2}) and (g(x)=\frac{x+2}{x-1}), what is the correct domain of (fg)?यदि (f(x)=\frac{x-1}{x+2}) और (g(x)=\frac{x+2}{x-1}) हैं, तो (fg) का सही डोमेन क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \mathbb{R}-{-2,1} )( \mathbb{R}-{-2,1} )
Although (fg=1), the original functions do not allow (x=-2) and (x=1). It is wrong to enlarge the domain after simplification.यद्यपि (fg=1) बनता है, मूल फलनों में (x=-2) और (x=1) अनुमत नहीं हैं। सरलीकृत अभिव्यक्ति से डोमेन बढ़ाना गलत है।
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