If \(f(x)=x-1\) and \(g(x)=\frac{1}{x-1}\), what is the value of \((f+g)(2)\)?

Correct answer: 2

For the sum of two functions, \((f+g)(x)=f(x)+g(x)\). Thus, \(f(2)=2-1=1\) and \(g(2)=\frac{1}{2-1}=1\), so \((f+g)(2)=1+1=2\). Option B gives the value of only one function, not their sum. Exam tip: evaluate each function separately and then add; although \(g(x)\) is undefined at \(x=1\), \(x=2\) is valid.