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If (f(x)=x) and (g(x)=x+1), what are the real solutions of ((f+g)(x)=(fg)(x))?यदि (f(x)=x) और (g(x)=x+1) हैं, तो ((f+g)(x)=(fg)(x)) के वास्तविक हल कौन से हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x=1+\sqrt{2},\ 1-\sqrt{2})(x=1+\sqrt{2},\ 1-\sqrt{2})
(2x+1=x^2+x) gives (x^2-x-1=0). The quadratic formula gives (x=\frac{1\pm\sqrt{5}}{2}), so the listed option pattern would be wrong.(2x+1=x^2+x) से (x^2-x-1=0) मिलता है। द्विघात सूत्र से (x=\frac{1\pm\sqrt{5}}{2}), इसलिए विकल्पों में त्रुटि होगी।
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