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If (f(x)=\sqrt{x^2-9}) and (g(x)=\frac{1}{x-4}), what is the domain of ((f+g)(x))?यदि (f(x)=\sqrt{x^2-9}) और (g(x)=\frac{1}{x-4}) हैं, तो ((f+g)(x)) का प्रांत क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x\le-3) or (x\ge3,\ x\ne4)(x\le-3) या (x\ge3,\ x\ne4)
For (\sqrt{x^2-9}), (x^2-9\ge0), and for the fraction (x\ne4). Thus (x\le-3) or (x\ge3), but (x=4) is removed.(\sqrt{x^2-9}) के लिए (x^2-9\ge0) और भिन्न के लिए (x\ne4)। इसलिए (x\le-3) या (x\ge3), पर (x=4) हटेगा।
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