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If \(f(x)=x^2-1\) and \(g(x)=x+1\), what is \(\left(\frac{f}{g}\right)(2)\) for (x\ne -1)?यदि \(f(x)=x^2-1\) और \(g(x)=x+1\) हों, तो (x\ne -1) के लिए \(\left(\frac{f}{g}\right)(2)\) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (3)(3)
\(\frac{x^2-1}{x+1}=x-1\), so at \(x=2\) the value is (1). Directly, \(f(2)=3\) and \(g(2)=3\), so the value is (1).\(\frac{x^2-1}{x+1}=x-1\), अतः \(x=2\) पर मान (1) नहीं बल्कि \(\frac{3}{3}\) से (1) होता है। सही गणना में \(f(2)=3\) और \(g(2)=3\), इसलिए मान (1) है।
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