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If (f(x)=\frac{x}{x-1}) and (g(x)=\frac{x-1}{x+1}), what is the simplified form and restriction of ((fg)(x))?यदि (f(x)=\frac{x}{x-1}) और (g(x)=\frac{x-1}{x+1}) हों, तो ((fg)(x)) का सरल रूप और प्रतिबंध क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{x}{x+1}), (x\ne 1,-1)(\frac{x}{x+1}), (x\ne 1,-1)
The simplified form is (\frac{x}{x+1}), but original denominators keep (x\ne 1,-1). Remember restrictions from cancelled factors too.सरल रूप (\frac{x}{x+1}) है, पर मूल हरों से (x\ne 1,-1) रहेगा। कटे हुए गुणनखंड का प्रतिबंध भी याद रखें।
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