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If \(f(x)=x^2-3x+2\) and \(g(x)=x-1\), what is \(\left(\frac{f}{g}\right)(3)\) for \(x \neq 1\)?यदि \(f(x)=x^2-3x+2\) और \(g(x)=x-1\) हैं, तो \(x \neq 1\) के लिए \(\left(\frac{f}{g}\right)(3)\) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (1)(1)
\(\frac{x^2-3x+2}{x-1}=\frac{(x-1)(x-2)}{x-1}=x-2\), so at \(x=3\) the value is (1). Factorisation makes division simple.\(\frac{x^2-3x+2}{x-1}=\frac{(x-1)(x-2)}{x-1}=x-2\), अतः \(x=3\) पर मान (1) है। गुणनखंडन से भाग सरल होता है।
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