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If \(f(x)=x^2+6x+9\) and \(g(x)=x+3\), what is \(\left(\frac{f}{g}\right)(0)\) for \(x \neq -3\)?यदि \(f(x)=x^2+6x+9\) और \(g(x)=x+3\) हैं, तो \(x \neq -3\) के लिए \(\left(\frac{f}{g}\right)(0)\) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (3)(3)
\(\frac{x^2+6x+9}{x+3}=\frac{(x+3)^2}{x+3}=x+3\), hence the value at \(x=0\) is (3). The perfect square identity is useful.\(\frac{x^2+6x+9}{x+3}=\frac{(x+3)^2}{x+3}=x+3\), अतः \(x=0\) पर मान (3) है। पूर्ण वर्ग पहचान उपयोगी है।
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