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If \(f(x)=x^2+3x+2\) and \(g(x)=x+1\), what is \(\left(\frac{f}{g}\right)(2)\) for \(x \neq -1\)?यदि \(f(x)=x^2+3x+2\) और \(g(x)=x+1\) हैं, तो \(x \neq -1\) के लिए \(\left(\frac{f}{g}\right)(2)\) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (4)(4)
\(\frac{x^2+3x+2}{x+1}=\frac{(x+1)(x+2)}{x+1}=x+2\), so at \(x=2\) the value is (4). Factorisation saves time.\(\frac{x^2+3x+2}{x+1}=\frac{(x+1)(x+2)}{x+1}=x+2\), इसलिए \(x=2\) पर मान (4) है। गुणनखंड बनाकर समय बचाएँ।
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