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Let \(f:A\to B\) and \(g:B\to C\). Which composite function is obtained by applying \(f\) first and then \(g\) to each element of \(A\)?

Answer and explanation

Correct answer: \(g\circ f:A\to C\), where \((g\circ f)(x)=g(f(x))\)

Applying \(f\) first sends \(x\in A\) to \(f(x)\in B\). Applying \(g\) next gives \(g(f(x))\in C\), so the composite is \(g\circ f\). Exam tip: in a composition, the function on the right acts first.

Related tags

Relations And FunctionsComposite FunctionsFunction CompositionReal FunctionsClass 11 MathematicsAlgebra Of Real FunctionsMathematicsClass 11 Mcq

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