If \(f(x)=x^2-16\) and \(g(x)=x+4\), what is the correct value of \(\left(\frac{f}{g}\right)(-1)\) for \(x \neq -4\)?यदि \(f(x)=x^2-16\) और \(g(x)=x+4\) हैं, तो \(x \neq -4\) के लिए \(\left(\frac{f}{g}\right)(-1)\) का सही मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (-5)(-5)
\(\frac{x^2-16}{x+4}=\frac{(x-4)(x+4)}{x+4}=x-4\), hence \(-1-4=-5\). Substitute carefully after simplification.\(\frac{x^2-16}{x+4}=\frac{(x-4)(x+4)}{x+4}=x-4\), अतः \(-1-4=-5\)। सरलीकरण के बाद सही मान रखें।
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