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If \(f(x)=x^2-16\) and \(g(x)=x+4\), what is \(\left(\frac{f}{g}\right)(-1)\) for \(x \neq -4\)?यदि \(f(x)=x^2-16\) और \(g(x)=x+4\) हैं, तो \(x \neq -4\) के लिए \(\left(\frac{f}{g}\right)(-1)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (3)(3)
\(\left(\frac{f}{g}\right)(x)=\frac{(x-4)(x+4)}{x+4}=x-4\), so at \(x=-1\) the value is (-5). Check directly as \(\frac{-15}{3}=-5\).\(\left(\frac{f}{g}\right)(x)=\frac{(x-4)(x+4)}{x+4}=x-4\), इसलिए \(x=-1\) पर मान (-5) होना चाहिए; पर सही जाँच में \(\frac{-15}{3}=-5\)।
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