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If \(f(x)=x^2+4x+4\) and \(g(x)=x+2\), what is \(\left(\frac{f}{g}\right)(x)\) for \(x \neq -2\)?यदि \(f(x)=x^2+4x+4\) और \(g(x)=x+2\) हैं, तो \(x \neq -2\) के लिए \(\left(\frac{f}{g}\right)(x)\) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x+2)(x+2)
\(\frac{x^2+4x+4}{x+2}=\frac{(x+2)^2}{x+2}=x+2\), where \(x \neq -2\). Write the zero of the denominator separately.\(\frac{x^2+4x+4}{x+2}=\frac{(x+2)^2}{x+2}=x+2\), जहाँ \(x \neq -2\)। हर का शून्य मान अलग से लिखें।
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