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If \(f(x)=2x^2\) and \(g(x)=x+1\), what is the value of \((f-g)(-2)\)?

Answer and explanation

Correct answer: 9

For the difference of two functions, \((f-g)(x)=f(x)-g(x)=2x^2-(x+1)\). At \(x=-2\), \(f(-2)=2(-2)^2=8\) and \(g(-2)=-2+1=-1\). Therefore, \((f-g)(-2)=8-(-1)=9\). The distractor 7 results from mishandling the negative value of \(g(-2)\). Exam tip: evaluate both functions separately before subtracting.

Related tags

Relations And FunctionsAlgebra Of FunctionsFunction DifferenceSubstitutionReal FunctionsAlgebra Of Real FunctionsMathematicsClass 11 Mcq

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