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If \(f(x)=x^2-9\) and \(g(x)=x-3\), what is \(\left(\frac{f}{g}\right)(x)\) for \(x \neq 3\)?यदि \(f(x)=x^2-9\) और \(g(x)=x-3\) हैं, तो \(x \neq 3\) के लिए \(\left(\frac{f}{g}\right)(x)\) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x+3)(x+3)
\(\left(\frac{f}{g}\right)(x)=\frac{x^2-9}{x-3}=\frac{(x-3)(x+3)}{x-3}=x+3\), where \(x \neq 3\). Always check that the denominator is not zero.\(\left(\frac{f}{g}\right)(x)=\frac{x^2-9}{x-3}=\frac{(x-3)(x+3)}{x-3}=x+3\), जहाँ \(x \neq 3\)। हर शून्य न हो, यह हमेशा जाँचें।
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