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If \(f(x)=x^2\) and \(g(x)=x+1\), what is the value of \((f-g)(0)\)?यदि \(f(x)=x^2\) और \(g(x)=x+1\) हों, तो \((f-g)(0)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: -1-1
For the difference of two functions, \((f-g)(x)=f(x)-g(x)\). Thus, \(f(0)=0^2=0\) and \(g(0)=0+1=1\), so \((f-g)(0)=0-1=-1\). Option B results from reversing the order of subtraction. Exam tip: For \((f-g)(a)\), calculate \(f(a)\) first and subtract \(g(a)\) from it.दो फलनों के अंतर के लिए \((f-g)(x)=f(x)-g(x)\)। इसलिए \(f(0)=0^2=0\) और \(g(0)=0+1=1\), अतः \((f-g)(0)=0-1=-1\)। विकल्प B में घटाव के क्रम को उलट दिया गया है। परीक्षा-टिप: \((f-g)(a)\) में पहले \(f(a)\) और फिर \(g(a)\) निकालकर घटाएँ।
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